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Math Example--Quadratics--Parabola Maximum and Minimum: Example 3

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# Parabola Maximum and Minimum: Example 3

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Quadratics

## Description

The maximum or minimum value of a parabola occurs at its vertex. For a parabola opening upward (a > 0), this point is a minimum. For a parabola opening downward (a < 0), it's a maximum. The vertex lies on the axis of symmetry.

For a quadratic function in standard form f(x) = ax² + bx + c, the x-coordinate of the vertex is given by x = -b/(2a), and the y-coordinate (maximum or minimum value) can be calculated by substituting this x-value into the original function.

This example presents f(x) = x² - 4x + 4. With a = 1 being positive, the parabola opens upward and has a minimum value. The x-coordinate of the vertex is x = -b/(2a) = 2. The maximum y-value is f(2) = 0. Therefore, the minimum value is 0, occurring at x = 2. The vertex (2, 0) is on the axis of symmetry x = 2.

For a complete collection of math examples related to Quadratics click on this link: __Math Examples: Quadratics Collection.__

Common Core Standards | CCSS.MATH.CONTENT.HSF.IF.C.8.A |
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Grade Range | 8 - 10 |

Curriculum Nodes |
Algebra• Quadratic Functions and Equations• Graphs of Quadratic Functions• Quadratic Equations and Functions |

Copyright Year | 2021 |

Keywords | parabola, maximum, minimum |